97b001e7c0
Small unsigned integers promote to signed int. As a consequence, if v is
a uint8_t, then (v << 24) yields an int, so the left shift is undefined
if the MSB is 1.
Cast to uint32_t to yield an unsigned value.
Reported by USAN (meson x -Db_sanitize=undefined):
runtime error: left shift of 255 by 24 places cannot be represented
in type 'int'
46 lines
993 B
C
46 lines
993 B
C
#ifndef BUFFER_UTIL_H
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#define BUFFER_UTIL_H
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#include "common.h"
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#include <stdbool.h>
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#include <stdint.h>
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static inline void
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buffer_write16be(uint8_t *buf, uint16_t value) {
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buf[0] = value >> 8;
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buf[1] = value;
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}
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static inline void
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buffer_write32be(uint8_t *buf, uint32_t value) {
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buf[0] = value >> 24;
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buf[1] = value >> 16;
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buf[2] = value >> 8;
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buf[3] = value;
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}
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static inline void
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buffer_write64be(uint8_t *buf, uint64_t value) {
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buffer_write32be(buf, value >> 32);
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buffer_write32be(&buf[4], (uint32_t) value);
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}
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static inline uint16_t
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buffer_read16be(const uint8_t *buf) {
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return (buf[0] << 8) | buf[1];
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}
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static inline uint32_t
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buffer_read32be(const uint8_t *buf) {
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return ((uint32_t) buf[0] << 24) | (buf[1] << 16) | (buf[2] << 8) | buf[3];
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}
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static inline uint64_t
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buffer_read64be(const uint8_t *buf) {
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uint32_t msb = buffer_read32be(buf);
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uint32_t lsb = buffer_read32be(&buf[4]);
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return ((uint64_t) msb << 32) | lsb;
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}
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#endif
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